检测一个函数是否是JavaScript原生函数的小技巧


在我的开发工作中经常会遇到需要判断一个函数是否是JavaScript原生函数的情况,有时候这是一个很必要的工作,你需要知道这个函数是浏览器自身提供的,还是由第三方封装、伪装成原生函数。当然,最好的方法是考察执行这个函数的toString方法的返回值。

The JavaScript

完成这个任务的方法非常简单:

更佳的方案:

复制代码 代码如下:

;(function() {

  // Used to resolve the internal `[[Class]]` of values
  var toString = Object.prototype.toString;
 
  // Used to resolve the decompiled source of functions
  var fnToString = Function.prototype.toString;
 
  // Used to detect host constructors (Safari > 4; really typed array specific)
  var reHostCtor = /^\[object .+?Constructor\]$/;

  // Compile a regexp using a common native method as a template.
  // We chose `Object#toString` because there's a good chance it is not being mucked with.
  var reNative = RegExp('^' +
    // Coerce `Object#toString` to a string
    String(toString)
    // Escape any special regexp characters
    .replace(/[.*+?^${}()|[\]\/\\]/g, '\\$&')
    // Replace mentions of `toString` with `.*?` to keep the template generic.
    // Replace thing like `for ...` to support environments like Rhino which add extra info
    // such as method arity.
    .replace(/toString|(function).*?(?=\\\()| for .+?(?=\\\])/g, '$1.*?') + '$'
  );
 
  function isNative(value) {
    var type = typeof value;
    return type == 'function'
      // Use `Function#toString` to bypass the value's own `toString` method
      // and avoid being faked out.
      ? reNative.test(fnToString.call(value))
      // Fallback to a host object check because some environments will represent
      // things like typed arrays as DOM methods which may not conform to the
      // normal native pattern.
      : (value && type == 'object' && reHostCtor.test(toString.call(value))) || false;
  }
 
  // export however you want
  module.exports = isNative;
}());


现在你也看到了,很复杂,但更强大。当然,这不是为了做安全防护,它只是给你提供是否是原生函数的相关信息。


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