C++实现将一个字符串中的字符替换成另一个字符串的方法


本文实例讲述了C++实现将一个字符串中的字符替换成另一个字符串的方法,分享给大家供大家参考。具体方法如下:

题目要求:

原地实现字符串中的每个空格替换成"%20",例如输入"We are happy", 输出"We%20are%20happy"
被替换的字符串当然不仅仅是空格,上面只是个例子
这是道很好的题目,也是百度面试中的一道题,题目不难,但是问题得考虑全面。这里给出如下实现代码:

#include <iostream>
#include <vector>
#include <cassert>

using namespace std;

int findNumberFirst(const char *str, const char *dest, vector<int>& pvec)
{
 if (str == NULL || dest == NULL)
 return 0;

 int pos = 0;
 int lenStr = strlen(str);
 int lenDest = strlen(dest);

 if (lenStr < lenDest)
 return 0;

 int count = 0;
 while (pos <= lenStr - lenDest)
 {
 if (strncmp(str + pos, dest, strlen(dest)) == 0)
 {
  pvec.push_back(pos);
  pos += lenDest;
  count++;
 }
 else
 {
  pos++;
 }
 }

 return count;
}

int findNumberLast(const char *str, const char *dest, vector<int> &pvec)
{
 if (str == NULL || dest == NULL)
 return 0;

 int strLen = strlen(str);
 int destLen = strlen(dest);

 if (strLen < destLen)
 return 0;

 int pos = 0;
 while (pos <= strLen - destLen)
 {
 if (strncmp(str + pos, dest, strlen(dest)) == 0)
 {
  pos += destLen;
  pvec.push_back(pos - 1);
 }
 else
 {
  pos++;
 }
 
 }

 return pvec.size();
}

void replaceArray(char *str, const char *src, const char *dest)
{
 if (str == NULL || src == NULL || dest == NULL)
 return;

 vector<int> pvec;
 int strLen = strlen(str);
 int srcLen = strlen(src);
 int destLen = strlen(dest);

 if (strLen < srcLen)
 return;

 int posBefore = 0;
 int posAfter = 0;

 if (srcLen < destLen)
 {
 int count = findNumberLast(str, src, pvec);
 if (count <= 0)
  return;
 
 posAfter = strLen + count * (destLen - srcLen) - 1;
 posBefore = strLen - 1;

 while (count > 0 && posBefore >= 0)
 {
  if (pvec[count - 1] == posBefore)
  {
  posAfter -= destLen;
  strncpy(str + posAfter + 1, dest, strlen(dest));
  count--;
  posBefore--;
  }
  else
  {
  str[posAfter--] = str[posBefore--];
  }
 }
 }
 else if (strLen > destLen)
 {
 int count = findNumberFirst(str, src, pvec);
 if (count <= 0)
  return;

 posAfter = 0;
 posBefore = 0;

 int i = 0;
 while (count >= 0 && posBefore < strLen)
 {
  if (count > 0 && pvec[i] == posBefore)
  {
  strncpy(str + posAfter, dest, strlen(dest));
  posAfter += destLen;
  count--;
  posBefore += srcLen;
  i++;
  }
  else
  {
  str[posAfter++] = str[posBefore++];
  }
 }
 str[posAfter] = '\0';
 }
}

void main()
{ 
 char *str = new char[100];
 if (str == NULL)
 return;
 memset(str, '\0', 100);

 const char *src = " ";
 const char *dest = "%20";
//case1: 只有1个空格
 strcpy(str, " ");

 replaceArray(str, src, dest);
 cout << "str: " << str << endl;

 replaceArray(str, dest, src);
 cout << "str: " << str << endl;

//case2: 两个空格
 strcpy(str, " ");

 replaceArray(str, src, dest);
 cout << "str: " << str << endl;

 replaceArray(str, dest, src);
 cout << "str: " << str << endl;

//case3: 正常情况
 strcpy(str, "we are happy");

 replaceArray(str, src, dest);
 cout << "str: " << str << endl;

 replaceArray(str, dest, src);
 cout << "str: " << str << endl;

//case3: 空格在前
 strcpy(str, " we are happy");

 replaceArray(str, src, dest);
 cout << "str: " << str << endl;

 replaceArray(str, dest, src);
 cout << "str: " << str << endl;

//case4: 空格在后
 strcpy(str, "we are happy ");

 replaceArray(str, src, dest);
 cout << "str: " << str << endl;

 replaceArray(str, dest, src);
 cout << "str: " << str << endl;

//case4: 没空格
 strcpy(str, "wearehappy");

 replaceArray(str, src, dest);
 cout << "str: " << str << endl;

 replaceArray(str, dest, src);
 cout << "str: " << str << endl;

//case5: 两边一样
 strcpy(str, "we are happy");

 replaceArray(str, src, dest);
 cout << "str: " << str << endl;

 src = "%20";
 assert(dest == "%20");
 replaceArray(str, dest, src);
 cout << "str: " << str << endl;
}

分析上述代码,很有意思的一个情况是srcLen和destLen或大或小的情形,其边界条件的判定不一样。比如we are happy为例子,从后往前拷贝时,count=2。

在count=0时,恰好将最前面的空格替换完成,we则不用重复拷贝。但是对于从前往后拷贝,当count=0时,最后面的happy将不会被拷贝。

希望本文所述实例对大家C++程序算法设计的学习有所帮助。


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