本文实例讲述了C#判断一天、一年已经过了百分之多少的方法。分享给大家供大家参考。具体如下：
这里写了四个函数，分别是
1.判断当前时间过了今天的百分之多少 static double DayTimePassed()
2.判断指定时间过了当日的百分之多少 static double DayTimePassed(DateTime dt)
3.判断当前时间过了今年的百分之多少 static double YearTimePassed()
4.判断指定时间过了当年的百分之多少 static double YearTimePassed(DateTime dt)
一、函数代码
/// <summary>
/// 判断当前时间过了今天的百分之多少
/// </summary>
/// <returns></returns>
static double DayTimePassed()
{
DateTime dt = DateTime.Now;
double Numerator = dt.Hour * 60 * 60 + dt.Minute * 60 + dt.Second;
double Denominator = 24 * 60 * 60;
return Numerator / Denominator;
}
/// <summary>
/// 判断指定时间过了当日的百分之多少
/// </summary>
/// <param name="dt"></param>
/// <returns></returns>
static double DayTimePassed(DateTime dt)
{
double Numerator = dt.Hour * 60 * 60 + dt.Minute * 60 + dt.Second;
double Denominator = 24 * 60 * 60;
return Numerator / Denominator;
}
/// <summary>
/// 判断当前时间过了今年的百分之多少
/// </summary>
/// <returns></returns>
static double YearTimePassed()
{
DateTime dt = DateTime.Now;
double Numerator = dt.DayOfYear * 24 * 60 * 60 +
dt.Hour * 60 * 60 + dt.Minute * 60 + dt.Second;
double Denominator =
(DateTime.IsLeapYear(dt.Year) ? 366 : 365) * 24 * 60 * 60;
return Numerator / Denominator;
}
/// <summary>
/// 判断指定时间过了当年的百分之多少
/// </summary>
/// <param name="dt"></param>
/// <returns></returns>
static double YearTimePassed(DateTime dt)
{
double Numerator = dt.DayOfYear * 24 * 60 * 60 +
dt.Hour * 60 * 60 + dt.Minute * 60 + dt.Second;
double Denominator =
(DateTime.IsLeapYear(dt.Year) ? 366 : 365) * 24 * 60 * 60;
return Numerator / Denominator;
}
二、Main函数调用
static void Main(string[] args)
{
Console.WriteLine(DateTime.Now.ToString());
Console.WriteLine("Day: " + DayTimePassed().ToString("P"));
Console.WriteLine("Day: " + DayTimePassed(DateTime.Now).ToString("P"));
Console.WriteLine("Year: " + YearTimePassed().ToString("P"));
Console.WriteLine("Year: " + YearTimePassed(DateTime.Now).ToString("P"));
Console.ReadLine();
}
三、运行结果
希望本文所述对大家的C#程序设计有所帮助。