HTML的form表单
用html的表单模拟一个文件上传的post请求，代码如下：
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
<title>File Upload</title>
</head>
<body>
<form enctype="multipart/form-data" action="test.php" method="POST">
<input type="hidden" name="MAX_FILE_SIZE" value="30000" />
Send this File:<input name="userfile" type="file"/>
<input type="submit" value="Send File" />
</form>
</body>
</html>
注意：
要确保文件上传表单的属性是 enctype="multipart/form-data",否则文件上传不了
PHP
首先，需要解释一下PHP的全局变量$_FILES，此数组包含了所有上传的文件信息
思路
1、生成40位的随机字符串作为文件名
2、根据文件是图片还是语音转存到不同的文件位置
3、暂时不做文件大小和文件类型的校验
function processFile($files, $type) {
$uploadName = null;
foreach ($files as $name => $value) {
$originalName = $value['name'];
$arr = explode(".", $originalName);
$postfix = $arr[count($arr) - 1];
$tmpPath = $value['tmp_name'];
$tmpType = $value['type'];
$tmpSize = $value['size'];
}
$newname = EhlStaticFunction::generateRandomStr(40).".".$postfix;
switch ($type) {
case 1 :
// 处理声音文件
$destination = VIDEOUPLOADDIR.$newname;
break;
case 2 :
// 处理图像文件
$destination = IMAGEUPLOADDIR.$newname;
break;
}
move_uploaded_file($tmpPath, $destination);
}
而获取所上传文件的后缀名则可以使用一下代码：
HTML
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title></title> <meta name="keywords" content=" keywords" /> <meta name="description" content="description" /> </head> <body> <form method="post" action="" enctype="multipart/form-data"> <input type="file" name="upfile" size="20" /> <input type="submit" name="submit" value="submit" /> </form> </body> </html>
PHP
<?PHP
if(isset($_POST['submit'])) {
$string = strrev($_FILES['upfile']['name']);
$array = explode('.',$string);
echo $array[0];
}
?>
结果示例：