是每一个 content 内容里面脏话的次数,基于另一个数组. 写到后面没什么思路了,应该怎么统计. ^_^
谢谢回答合各位的回答,学习了多种写法。 用了qvga提供的第一种,后面加上array_sum统计了总数。 在次谢谢^_^
$arr = array('2b', 'fuck');
$con = array(
array(
'content'=>'asdfasdf2bsdfasdf2dfasdfuck'
),
array(
'content'=>'asdfasdf2asdfasdf2dfasdfuck'
),
array(
'content'=>'asdfasdfuckbsdfasdf2dfasdfuck'
),
);
foreach($con as $ck => $cv) {
foreach ($arr as $av) {
if (($pos = strpos($cv['content'], $av)) !== false) {
$cv['checkCount'][$av] = recursionSearch($cv['content'], $av, $pos, 1);
}
}
$con[$ck] = $cv;
}
print_r($con); //
function recursionSearch($haystack, $needle, $offset=0, $res=0 ) {
$offset += strlen($needle);
if (($pos = strpos($haystack, $needle, $offset)) === false) {
return $res;
} else {
return recursionSearch($haystack, $needle, $pos, $res+1 );
}
}
// 打印结果
/**
Array
(
[0] => Array
(
[content] => asdfasdf2bsdfasdf2dfasdfuck
[checkCount] => Array
(
[2b] => 1
[fuck] => 1
)
)
[1] => Array
(
[content] => asdfasdf2asdfasdf2dfasdfuck
[checkCount] => Array
(
[fuck] => 1
)
)
[2] => Array
(
[content] => asdfasdfuckbsdfasdf2dfasdfuck
[checkCount] => Array
(
[fuck] => 2
)
)
)
**/
完美的解决方法想不出来,毕竟还是渣渣。
想到一个比较丑的方法,看看就行:
$str = "1111111111111112b22222222caonima22222222";
$words = ['2b','caonima'];
$res = [];
foreach($words as $word){
$res[$word] = count(explode($word, $str))-1;
}
return $res;
如果说是只统计脏话次数,并不要求每一个脏话的次数,之前写过一个根据多个key切割字符串的函数
$str = "1111111111111112b22222222caonima22222222";
$words = ['2b','caonima'];
function many_explode($cutKey,$string){
$return=[];
$key=0;
for($i=0;$i<strlen($string);$i++){
if(in_array($string[$i], $cutKey)){
$key++; //当前字符在 cutKey 中,跳过,并另起一行
}else{
$return[$key]=isset($return[$key])?$return[$key].$string[$i]:$string[$i];
}
}
return $return;
}
return count(many_explode($words, $str)) -1;
换汤不换药
1,所有的脏话的关键词建立一个表.
2,内容context 做全文索引.
3,使用mysql自带的函数检索locate,或者你用like也可以.