underscore.js 数组拆分新问题

var message  =message: 
                        [  {n:"jerry",a:"static/images/liuyan.jpg",from:"1", to: "10",msg:"在吗555",date:"2010-12-23"},
                           {n:"jerry",a:"static/images/liuyan.jpg",from:"1", to: "10",msg:"回来了吗",date:"2019-12-23"},
                           {n:"刘云",a:"static/images/ly.jpg",from:"10", to: "1",msg:"回来了:)",date:"2019-12-3"},
                           {n:"刘云",a:"static/images/ly.jpg",from:"10", to: "1",msg:"给你带了东西",date:"2019-12-23"},
                           {n:"刘云",a:"static/images/ly.jpg",from:'10', to: "1",msg:"累死了",date:"2012-1-1"},
                           {n:"jerry",a:"static/images/liuyan.jpg",from:"1", to: "10",msg:"在吗555bbbbbb",date:"2010-12-23"},
                           {n:"刘云",a:"static/images/ly.jpg",from:'10', to: "1",msg:"累死了333333",date:"2012-1-1"},

                        ];

拆分为：

 var message  =message: 
                        [  [{n:"jerry",a:"static/images/liuyan.jpg",from:"1", to: "10",msg:"在吗555",date:"2010-12-23"},
                           {n:"jerry",a:"static/images/liuyan.jpg",from:"1", to: "10",msg:"回来了吗",date:"2019-12-23"}],

                           [{n:"刘云",a:"static/images/ly.jpg",from:"10", to: "1",msg:"回来了:)",date:"2019-12-3"},
                            {n:"刘云",a:"static/images/ly.jpg",from:"10", to: "1",msg:"给你带了东西",date:"2019-12-23"},
                            {n:"刘云",a:"static/images/ly.jpg",from:'10', to: "1",msg:"累死了",date:"2012-1-1"}],

                           
                           [{n:"jerry",a:"static/images/liuyan.jpg",from:"1", to: "10",msg:"在吗555bbbbbb",date:"2010-12-23"}],
                           [{n:"刘云",a:"static/images/ly.jpg",from:'10', to: "1",msg:"累死了333333",date:"2012-1-1"}]

                        ];

每次收到对方的新消息，需要另起一行，如果一直是自己说话，内容还在这行里面。
如何用underscore 实现。

---

只能用 each 了.

var e = [],//保存结果
    f = [] ;//保存连续的数据项

_.each(a, function(b){
    //如果当前内容是 空
    if(f.length === 0){
        f = [b];//直接仍进去
    }else{
        //如果当前的这个 与上一个 一样
        if(b.n === f[f.length - 1].n){
            //仍进 f 数组里
            f.push(b);
        }else{//不一样的情况
            //将 f 仍进 e中
            e.push(f);
            //将当前的这个仍到f中
            f = [b];
        }
    }
});

//最后, 如果f里还有内容
if(f.length > 0){
    //把剩下的数据仍到 e 里
    e.push(f);
}

//输出结果
console.log(JSON.stringify(e, 0 , '\t'))

结果:

[
    [
        {
            "n": "jerry",
            "a": "static/images/liuyan.jpg",
            "from": "1",
            "to": "10",
            "msg": "在吗555",
            "date": "2010-12-23"
        },
        {
            "n": "jerry",
            "a": "static/images/liuyan.jpg",
            "from": "1",
            "to": "10",
            "msg": "回来了吗",
            "date": "2019-12-23"
        }
    ],
    [
        {
            "n": "刘云",
            "a": "static/images/ly.jpg",
            "from": "10",
            "to": "1",
            "msg": "回来了:)",
            "date": "2019-12-3"
        },
        {
            "n": "刘云",
            "a": "static/images/ly.jpg",
            "from": "10",
            "to": "1",
            "msg": "给你带了东西",
            "date": "2019-12-23"
        },
        {
            "n": "刘云",
            "a": "static/images/ly.jpg",
            "from": "10",
            "to": "1",
            "msg": "累死了",
            "date": "2012-1-1"
        }
    ],
    [
        {
            "n": "jerry",
            "a": "static/images/liuyan.jpg",
            "from": "1",
            "to": "10",
            "msg": "在吗555bbbbbb",
            "date": "2010-12-23"
        }
    ],
    [
        {
            "n": "刘云",
            "a": "static/images/ly.jpg",
            "from": "10",
            "to": "1",
            "msg": "累死了333333",
            "date": "2012-1-1"
        }
    ]
]