这样写可以正常跳转:
echo "<script>";
echo "window.location.href = '$url'";
echo "</script>";
而下面代码服务器返回空白页面,没有执行我的命令,请问是怎么回事?php小白,照葫芦画瓢写的代码:
echo "<script>";
echo "function()
{
alert($error_msg);
setTimeout(window.location.href = '$url',5);
}";
echo "</script>";
楼上仁兄正解
<?php
$url = "http://www.baidu.com";
$error_msg = "error";
echo "<script>";
echo "function jump()
{
alert('$error_msg');
window.location.href = '$url';
}
setTimeout(jump, 3000);
";
echo "</script>";
你js部分只是定义了函数没有调用啊
setTimeout(func,5);
前面func是一个方法
echo "<script>";
echo "function func()
{
alert($error_msg);
window.location.href = '$url';
}";
setTimeout(func,5);
echo "</script>";