#encoding=utf-8
import socket,time
tcpT4Client = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
print "Done........"
tcpT4Client.connect(('192.168.0.150', 8000))
print "TCP IPv4 TCP mode connecting..."
while True:
time.sleep(1)
tcpT4Client.send('7E1501046601020000837E')
不知道怎么接受数据。。求指教
https://wiki.python.org/moin/TcpCommunication
官方的例子改了一下:
#!/usr/bin/env python
import socket
TCP_IP = '192.168.0.150'
TCP_PORT = 8000
BUFFER_SIZE = 20 # Normally 1024, but we want fast response
s = socket.socket(socket.AF_INET, socket.SOCK_STREAM)
s.bind((TCP_IP, TCP_PORT))
s.listen(1)
conn, addr = s.accept()
print 'Connection address:', addr
while 1:
data = conn.recv(BUFFER_SIZE)
if not data: break
print "received data:", data
conn.send(data) # echo
conn.close()
楼上给的是对端(server)接收,题主没说清是本端还是对端的接收
这里说下本端(client)接收
# 在send之后接收服务器的回应
data = tcpT4Client.recv(1024)
print data
1024是接收的最大长度,可自己设置