python输出列表，只输出某个值

list = [{'Alice': '2341', 'Beth': '9102', 'Cecil': '3258'},{'Alice': '123', 'Beth': '456', 'Cecil': '789'},{'Alice': '1111', 'Beth': '2222', 'Cecil': '3333'}]

print  list

如何只输出Alice里面的值
最后输出结果为：
2341
123
111

---

list_example = [{'Alice': '2341', 'Beth': '9102', 'Cecil': '3258'}, {'Alice': '123', 'Beth': '456', 'Cecil': '789'},
                {'Alice': '1111', 'Beth': '2222', 'Cecil': '3333'}]


# print  list

def filter_list(dict_list, key):
    for dictionary in dict_list:
        print dictionary.get(key, None)


filter_list(list_example, "Alice")

---

list是 Python 内置类的名称，不建议用list作为变量名。

for item in your_list:
    print item['Alice']