Thinkphp 使用join()方法以后无法在使用field()方法

    //  获取所有的支出记录
    public function gainHavingPayRecord(){
        $m = M('pay_record');
        $result = $m->order('payrecord_pay_time desc')
            ->join("LEFT JOIN x_account ON x_pay_record.payrecord_payer = x_account.account_id")
            ->field('account_phone,account_password,account_salt,account_alipay,account_createtime,account_cash,account_bank,account_isdelete',true)
            ->select();
        dump($result[0]);
        return $result;
    }

之后输出的数据所有account表中的数据都被过滤了 只输出了pay_record表中的数据

array(10) {
  ["payrecord_id"] => string(1) "1"
  ["payrecord_pay_time"] => string(1) "0"
  ["payrecord_payer"] => string(1) "1"
  ["payrecord_payment_type"] => string(1) "1"
  ["payrecord_item_category"] => string(1) "1"
  ["payrecord_item_son_category"] => string(1) "1"
  ["payrecord_sum"] => string(4) "3000"
  ["payrecord_record_time"] => string(10) "1467428218"
  ["payrecord_confirm"] => string(1) "0"
  ["payrecord_confirm_time"] => string(1) "0"
}

官方文档是这么说的

请问还有有什么方法可以吧这些字段过滤掉吗

->field('account_phone,account_password,account_salt,account_alipay,account_createtime,account_cash,account_bank,account_isdelete',true)

其实我也可以直接把想要使用的数据存到一张表里就可以不用join()方法减少服务器压力.但是遇到这种问题我想解决了 ,一旦那天非常迫切的需要这样处理数据也不至于无从下手.

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字段前加上表名或者表的别名：

$result = M('x_account as acc')->join('x_pay_record as rec on rec .payrecord_payer = acc.account_id')->field('acc.字段1, acc.字段2, rec.字段3, rec.字段4')->select(); 

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field里面要加上表名field('表名.account_phone,表名.account_password,表名.account_salt,表名.account_alipay,表名.account_createtime,表名.account_cash,表名.account_bank,表名.account_isdelete',true)

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应该有.吧，比如说pay_record.acc

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你可以先用getLastSql看下sql语句是怎么写的，join和field应该是可以结合的，所以你再检查一下你的关键字。
加一句test

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join后必须要使用表名的 因为mysql不知道你要哪张表的哪个字段过滤那个表的哪个字段