int8_t读入数据(进制转换的程序)

// 使用int正常运行, 改成int8_t num始终读成0

#include <stdio.h>
#include <stdint.h>
void convert(int8_t, int8_t);

int main(int argc, char const *argv[]) {
    int8_t num;
    int8_t b;
    printf("enter a number:\n");
    while (1 == scanf("%d", &num)) {
        scanf("%d", &b);
        printf("%d %d\n", num, b);
        printf("Code: ");
        convert(num, b);
        putchar('\n');
        printf("enter a integer (q to quit):\n");
    }
    printf("done.\n");
    
    getchar();
    return 0;
}

void convert(int8_t n, int8_t base) {
    if (n >= base)
        convert(n / base, base);
    printf("%d", n % base);
    return;
}