我要模拟一个多文件提交
<form enctype="multipart/form-data" action="http://192.168.29.65/UploadFile" method=post>
load multi files :<br>
<input name="userfile" type="file"><br>
<input name="userfile" type="file"><br>
<input name="userfile" type="file"><br>
<input name="userfile" type="file"><br>
text field :<input type="text" name="text" value="text"><br>
<input type="submit" value="提交"><input type=reset>
</form>后端以一个userfile的文件数组接受
我怎么使用HttpClient的HttpPost来模拟文件数组上传。我单个文件会，但是想上面一样使用一个name的文件数组就不知道怎么写
RFC2388 - Returning Values from Forms: multipart/form-data
Stackoverflow - what-does-enctype-multipart-form-data-mean
请求报文（来自Stackoverflow的回答）：
POST / HTTP/1.1
[[ Less interesting headers ... ]]
Content-Type: multipart/form-data; boundary=---------------------------735323031399963166993862150
Content-Length: 834
-----------------------------735323031399963166993862150
Content-Disposition: form-data; name="text1"
text default
-----------------------------735323031399963166993862150
Content-Disposition: form-data; name="text2"
aωb
-----------------------------735323031399963166993862150
Content-Disposition: form-data; name="file1"; filename="a.txt"
Content-Type: text/plain
Content of a.txt.
-----------------------------735323031399963166993862150
Content-Disposition: form-data; name="file2"; filename="a.html"
Content-Type: text/html
<!DOCTYPE html><title>Content of a.html.</title>
-----------------------------735323031399963166993862150
Content-Disposition: form-data; name="file3"; filename="binary"
Content-Type: application/octet-stream
aωb
-----------------------------735323031399963166993862150--把name改成userfile[]