我想通过这条 api 获取手机号的区域信息http://virtual.paipai.com/extinfo/GetMobileProductInfo?mobile=13333333333&amount=10000
正常应该是这样的({mobile:'13333333333',province:'河北',isp:'中国电信',stock:'1',amount:'10000',maxprice:'0',minprice:'0',cityname:'秦皇岛'});
但是现在报错httplib.BadStatusLine: ''
在浏览器打开是没有问题的，下面是执行的代码，谢谢大家了。
import httplib
import urllib
headers = {"Content-type":"text/html; charset=gb2312", "Accept": "text/html,application/xhtml+xml,application/xml;q=0.9,image/webp,*/*;q=0.8","Accept-Encoding":"gzip,deflate,sdch","Accept-Language":"zh-CN,zh;q=0.8","Cache-Control":"max-age=0","Connection":"keep-alive" ,"User-Agent":"Mozilla/5.0 (Windows NT 6.3; WOW64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/35.0.1916.153 Safari/537.36 SE 2.X MetaSr 1.0", "Cookie": "visitkey=52562270763683935"}
conn = httplib.HTTPConnection("112.90.77.176:80")
conn.request("GET", "/extinfo/GetMobileProductInfo",urllib.urlencode({'mobile': 15226922222,'amount':10000}),headers)
r1 = conn.getresponse()
print r1.status, r1.reason
连接时使用IP, 在HTTP请求头里可以使用Host字段指定请求的主机的域名.
附改后的代码:
import httplib
import urllib
headers = {"Host":"virtual.paipai.com","Content-type":"text/html; charset=gb2312", "Accept": "text/html,application/xhtml+xml,application/xml;q=0.9,image/webp,*/*;q=0.8","Accept-Encoding":"gzip,deflate,sdch","Accept-Language":"zh-CN,zh;q=0.8","Cache-Control":"max-age=0","Connection":"keep-alive" ,"User-Agent":"Mozilla/5.0 (Windows NT 6.3; WOW64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/35.0.1916.153 Safari/537.36 SE 2.X MetaSr 1.0", "Cookie": "visitkey=52562270763683935"}
conn = httplib.HTTPConnection("112.90.77.176:80")
conn.request("GET", "/extinfo/GetMobileProductInfo",urllib.urlencode({'mobile': 15226922559,'amount':10000}),headers)
r1 = conn.getresponse()
print r1.status, r1.reason
conn = httplib.HTTPConnection("112.90.77.176:80")
改为
conn = httplib.HTTPConnection("virtual.paipai.com")