想写一个自动脚本
先测试生成的配置文件
/usr/local/nginx/sbin/nginx -t -c /usr/local/nginx/conf/test.conf如果测试成功就覆盖nginx.conf 不成功就返回错误
然而不知道如何获取执行测试指令之后的信息 指令都是执行成功
[root@arbiter nginx]# /usr/local/nginx/sbin/nginx -t -c /usr/local/nginx/conf/nginx.conf
nginx: the configuration file /usr/local/nginx/conf/nginx.conf syntax is ok
nginx: configuration file /usr/local/nginx/conf/nginx.conf test is successful
[root@arbiter nginx]# echo $?
0
[root@arbiter nginx]# /usr/local/nginx/sbin/nginx -t -c /usr/local/nginx/conf/mime.types
nginx: [emerg] "types" directive is not allowed here in /usr/local/nginx/conf/mime.types:2
nginx: configuration file /usr/local/nginx/conf/mime.types test failed
[root@arbiter nginx]# echo $?
1
bash 中 $? 用来获取上一条命令的返回值，0 为正常，其他值为异常。
如果需要获取命令输出，可以按一下方式操作：
[root@arbiter nginx]# a="`/usr/local/nginx/sbin/nginx -t -c /usr/local/nginx/conf/mime.types 2>&1`"
[root@arbiter nginx]# echo $a
nginx: [emerg] "types" directive is not allowed here in /usr/local/nginx/conf/mime.types:2 nginx: configuration file /usr/local/nginx/conf/mime.types test failed
其中2>&1的作用是将标准错误重定向到标准输出